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A stadium has 52,00 seats. Seats sell for $35 in section A, $20 in section B, and $15 in section c. The number of seats in section A equals the total number of seats in both b and c. Suppose the stadium takes in $1,370,500 from each sold-out event.How many seats does each section hold

Answer 1

Let the Total number of A seats be A  Let the Total number of B seats be B  Let the Total number of C seats be C  Given that the Total number of stadium seats = 52000  ⇒ A + B + C = 52000  It is also mentioned that the number of seats in section A is equal to the total number of seats in both B and C  ⇒ A = B + C  substituting the Value of A = B + C in A + B + C = 52000  ⇒ A + A = 52000  ⇒ 2A = 52000  ⇒ A = 26000  ⇒ The Number of Seats of A = 26000  ⇒ The Number of Seats of Both B and C = 26000       (since A = B + C)  Given that Cost of Each seat of A = 35$  Cost of Each seat of B = 20$  Cost of Each seat of C = 15$  The Total Cost of all the seats = 1370500$  ⇒ 35(A) + 20(B) + 15(C) = 1370500  dividing the entire equation with 5 we get :  ⇒ 7A + 4B + 3C = 274100  but we know that number of seats of A = 26000  ⇒ 7(26000) + 4B + 3C = 274100  ⇒ 4B + 3C = 274100 - 182000  ⇒ 4B + 3C = 92100  but we know that B + C = 26000 ⇒ C = 26000 - B  ⇒ 4B + 3(26000 - B) = 92100  ⇒ 4B + 78000 - 3B = 92100  ⇒ B = 92100 - 78000  ⇒ B = 14100  ⇒ The Total Number of seats of B = 14100  As B + C = 26000  ⇒ 14100 + C = 26000  ⇒ C = 26000 - 14100  ⇒ C = 11900  ⇒ The Total number of seats of C = 11900  So the Stadium Holds a Total number of 52000 seats and In those 52000 seats A section holds 26000 seats and B section holds 14100 seats and C section holds 11900 seats.  Read more on Brainly.in - https://brainly.in/question/5736105#readmore

Answer 2

A = 26000 seats

B = 14100 seats

C = 11900 seats