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A stadium has 52,00 seats. Seats sell for $35 in section A, $20 in section B, and $15 in section c. The number of seats in section A equals the total number of seats in both b and c. Suppose the stadium takes in $1,370,500 from each sold-out event.How many seats does each section hold
Answers
Let the Total number of A seats be A Let the Total number of B seats be B Let the Total number of C seats be C Given that the Total number of stadium seats = 52000 ⇒ A + B + C = 52000 It is also mentioned that the number of seats in section A is equal to the total number of seats in both B and C ⇒ A = B + C substituting the Value of A = B + C in A + B + C = 52000 ⇒ A + A = 52000 ⇒ 2A = 52000 ⇒ A = 26000 ⇒ The Number of Seats of A = 26000 ⇒ The Number of Seats of Both B and C = 26000 (since A = B + C) Given that Cost of Each seat of A = 35$ Cost of Each seat of B = 20$ Cost of Each seat of C = 15$ The Total Cost of all the seats = 1370500$ ⇒ 35(A) + 20(B) + 15(C) = 1370500 dividing the entire equation with 5 we get : ⇒ 7A + 4B + 3C = 274100 but we know that number of seats of A = 26000 ⇒ 7(26000) + 4B + 3C = 274100 ⇒ 4B + 3C = 274100 - 182000 ⇒ 4B + 3C = 92100 but we know that B + C = 26000 ⇒ C = 26000 - B ⇒ 4B + 3(26000 - B) = 92100 ⇒ 4B + 78000 - 3B = 92100 ⇒ B = 92100 - 78000 ⇒ B = 14100 ⇒ The Total Number of seats of B = 14100 As B + C = 26000 ⇒ 14100 + C = 26000 ⇒ C = 26000 - 14100 ⇒ C = 11900 ⇒ The Total number of seats of C = 11900 So the Stadium Holds a Total number of 52000 seats and In those 52000 seats A section holds 26000 seats and B section holds 14100 seats and C section holds 11900 seats. Read more on Brainly.in - https://brainly.in/question/5736105#readmore
A = 26000 seats
B = 14100 seats
C = 11900 seats