Question

Help needed in 6th one

Answer 1

Tan^2/ (sec^2 - 1)^2 = 1 + cos / 1 - cos

Take LHS

= (sin^2 / cos^2) / (sec^2 - 2sec + 1)

= sin^2 / cos^2 (sec - 1)^2

= sin^2 / cos^2(1/cos - 1)^2

= sin^2 /cos^2(1-cos)^2 /cos^2

= (1-cos^2) / (1-cos)^2

= (1+cos)(1-cos) / (1-cos^2)

= 1 + cos / 1 - cos

= RHS

THANKS

Answer 2

I hope so it is helpful to you