Question

Help needed please
Please help me here

Answer 1

if 2a+3b=7
and
ab=2

then
(2a+3b)2 -2= 4a2+9b2
(7)2 -2 = 4a2+9b2
49 -2= 4a2+9b2
4a2+9b2=47

Answer 2

(2a+3b)^2=4a^2+9b^2+2(2a)(3b)
(2a+3b)^2=4a^2+9b^2+12ab
then putting the values

7^2=4a^2+9b^2+12(2)
49=4a^2+9b^2+24
49-24=4a^2+9b^2
4a^2+9b^2=25