Question

Help out in it.....❤️❤️❤️❤️❤️
#_no spams....
plzzz​

Answer 1

$DX÷(X+1)(X+2)$

$DX/(X+1)(X+2)=A/(X+1) +$ $B/(X+2)$

$1=AX+2A+BX+B$

$1=X(A+B)+(2A+B)$

A+B=0----------equation(1)

2A+B=1------------equation(2)

B=-A

Keeping the value of option 1 to B in 2--

2A-A=1

A=1

put the value of A equation 1st-----

B=-1

$=A/(X+1) + B/(X+2)$

put the value of A,B---

$=1/(X+1) +1/(X+2)$ ✏️✏️✏️✏️

intergration ----

$=log^(X+1)+log^(X+2)+C$✏️✏️

____please follow me____

✌️✍️✍️ please mark it brainlist answer..

Answer 2

Answer:

hope it helps you ! mark as brainliest