Question

Help out please ✔️✔️✔️✔️

❤ solve the inequation ❤​

Answer 1

Solving using inequality rules:-

postive interger can be multiplied to right side in last 2nd step

$\frac{2x + 3}{3} - \frac{3x - 1}{4} \geqslant 0 \\ \\ \frac{8x + 12 - 9x - 3}{12} \geqslant \: 0 \\ \\ \frac{ - x + 9}{12} \geqslant 0 \\ \\ - x + 9 \geqslant 0 \\ \\ x \leqslant 9$

Answer :- X will be less than or equal to nine

(- ∞, 9]

Answer 2

Step-by-step explanation:

$Given:\frac{2x+3}{3} \geq \frac{3x-1}{4}$

$=(2x + 3) * 4 \geq 3 * (3x - 1)$

$=8x + 12 \geq 9x - 3$

$= 8x \geq 9x - 15$

$=> -x \geq -15$

$=> x \leq 15$

Solution: x ≤ 15

Interval : (-∞,15]

Hope it helps!