help physics tension formula koisa galat mt batana
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Answer:
acceleration of block and trolley = 0.96 m/s²
and , Tension in the string = 27.2 N
Explanation:
Given,
the coefficient of kinetic friction between the trolly and the surface is 0.04.
To find : Acceleration of block and trolley system and tension in the string.
Solution:
For block,m = 3kg, W = 30 N,
Applying Newton's law in vertical direction,
30 - T = 3 a ....{i)
For trolley,m = 20kg
Applying Newton's law in horizontal direction,
T - fk = 20 a ....(ii)
where, fk = kinetic friction = μk *N = 0.04 * 20 * 10 = 8 N
Putting value of fk and solving eq(i) and ii:
We will obtain T = 27.2 N and a = 0.96 m/s²
Therefore, acceleration of block and trolley = 0.96 m/s²
and , Tension in the string = 27.2 N
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