Question

Help please!!!!! ✌ ​

Answer 1

Refer To the attachment!!!!

Answer 2

Answer:

$\frac{1}{a + b + x} = \frac{1}{a} + \frac{1}{b} + \frac{1}{x} \\ \frac{1}{a + b + x} - \frac{1}{x} = \frac{1}{a} + \frac{1}{b} \\ \frac{x - (a + b + x)}{x(a + b + x)} = \frac{a + b}{ab} \\ \frac{ - a + b}{x(a + b + x)} = \frac{a + b}{ab} \\ - ab(a + b) = x(a + b + x)(a + b) \\ x(a + b + x) + ab = 0 \\ ax + bx + {x}^{2} + ab = 0 \\ x(x + a) + b(x + a) = 0 \\ (x + b)(x + a) = 0 \\ x + a = 0 \: or \: x + b = 0 \\ x = - a \: or \: x = - b$