Question

help please!!!!!!!!!!!

Answer 1

We have been given a set of capacitors attached to terminal P and Q. We need to find out the the equivalent capacitance.

We shall perform "potential drop assignment method " to solve thos problem

After analysing the potential drops along the capacitors, we can draw a simplified circuit as shown in the figure :

In the upper part of the circuit , we get :

$\dfrac{1}{C_{2}} = \dfrac{1}{C} + \dfrac{1}{2C}$

$= > C_{2} = \dfrac{2C}{3}$

In the lower part of the circuit , we have a single capacitor of C in parallel with above capacitors.

So net equivalent Capacitance is :

$C eq. = \dfrac{2C}{3} + C = \dfrac{5C}{3}$

Putting the value of C as parallel plate capacitor , we get:

$C eq. = \dfrac{5C}{3} = \dfrac{5\epsilon_{0} A}{3d}$