Question

প্রতিক্ষণ কি ধরনের সমাস

help please​

Answer 1

Answer:

Answer:

(c) 11 g

Procedure:

How to reach final answer?

Volume \longrightarrow⟶ Moles \longrightarrow⟶ Molar mass

Use STP volume relation to find moles.

Use moles and given mass to get final molar mass.

Explanation:

#Using volumes to find moles

Volume of 1 mole of an ideal gas at STP = 22.4 L

Volume of this gas at STP = 11.21 L

Let the no of moles be x,

Now using ratios,

\begin{gathered}\\\tt \dfrac{22.4}{11.21} = \dfrac{1}{x}\end{gathered}

11.21

22.4

=

x

1

#Using moles to find mass with given data

Solving for x returns 1.99 approximately equal to 2.

There are 2 moles of the gas in 11.21 L,

Now that we know that these 2 moles weigh 22g,

Therefore one mole must weigh 11 g.

this is answer for your upper question.