Question

Help Please !!!!!!!!!!!!​

Answer 1

Answer:

proof is in the image

Step-by-step explanation:

proof is in the image

Answer 2

Step-by-step explanation:

Using given equation

$\\\tt\dfrac{ \tan \theta }{ \dfrac{ { \sin }^{3} \theta }{ \cos \theta} + \sin \theta \cos \theta }$

Multiplying numerator and denominator by $\\\tt \cos \theta$

We get,

$\\\tt \dfrac{ \sin \theta }{\sin ^{3} \theta + \sin \theta \cos ^{2} \theta} \\ \\\tt \dfrac{ \sin \theta }{\sin \theta(\sin ^{2} \theta + \cos ^{2} \theta)} \\\tt = \dfrac{ \sin \theta }{\sin \theta} \\ = 1$

Identities used:

$\\\tt \sin^2 \theta + cos^2\theta = 1$