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Given equations are :-
0.2x + 0.3y = 1.3 .......(1)
0.4x + 0.5y = 2.3
=> 0.4x = 2.3 - 0.5y
=> x = (2.3 - 0.5y)/0.4 ....(2)
substitute value of x in equation (1), we get
0.2 (2.3 - 0.5y)/0.4 + 0.3y = 1.3
=> 2.3 - 0.5y + 0.6y = 2.6
=> 0.1y = 2.6 - 2.3
=> y = 0.3/0.1
=> y = 3
put this value in equation (2), we get
x = (2.3 - 0.5×3)/0.4
=> x = (2.3 - 1.5)/0.4
=> x = 0.8/0.4
=> x = 2
Hence, x = 2 and y = 3
【 Hope it helps you 】
Given equations are :-
0.2x + 0.3y = 1.3 .......(1)
0.4x + 0.5y = 2.3
=> 0.4x = 2.3 - 0.5y
=> x = (2.3 - 0.5y)/0.4 ....(2)
substitute value of x in equation (1), we get
0.2 (2.3 - 0.5y)/0.4 + 0.3y = 1.3
=> 2.3 - 0.5y + 0.6y = 2.6
=> 0.1y = 2.6 - 2.3
=> y = 0.3/0.1
=> y = 3
put this value in equation (2), we get
x = (2.3 - 0.5×3)/0.4
=> x = (2.3 - 1.5)/0.4
=> x = 0.8/0.4
=> x = 2
Hence, x = 2 and y = 3
【 Hope it helps you 】
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