Question

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Answer 1

the figure represent a trapezium PQRS

in a Trapezium the sides are parallel so they form of co interior angle whose sum is 180°

$(a + 10) + (a - 20) = 180°$

$2a - 10 = 180°$

$2a = 190°$

$a = \frac{190}{2}$

$a = 95°$

putting the value of a in both angles

$95° + 10° = 105°$

$95° - 20° = 75°$

Answer 2

Answer:

Step-by-step explanation:

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