Question

help please..

A stone is thrown with an initial velocity of 20 m/s at an angle of 50° on the horizontal surface.


Find:

a. maximum height

b. total time of flight

c. range

Answer 1

Answer:

Explanation:

maximum height=(v^2* sin^2x)/2g

reslove v into two components v cos x(horizontal),v sin x(vertical)

    =20^2*sin^2 50/20=11.7 m

total time of flight=2vsinx/g=2*20*sin 50/10=3.06s

range=v^2 sin 2x/g=400*sin 100/10=39.3 m

Answer 2

Answer:

Refer the answer given in the image.

You're welcome.