Math, asked by guptagungun827, 28 days ago

help please


ABCD is rhombus with angle ACD is equals to 40 degree find the measure of angle ADB​

Answers

Answered by y666
0

Answer:

Step-by-step explanation:

answer is 57da

Answered by sakshimane92561
0

Answer:

IABCD is a rhombus and ACB = 40 deg. What is the value of <ADB?

IABCD is a rhombus and ACB = 40 deg. What is the value of <ADB?Since <ACB = 40 deg, <BCD = 2*<ACB = 80 deg.

IABCD is a rhombus and ACB = 40 deg. What is the value of <ADB?Since <ACB = 40 deg, <BCD = 2*<ACB = 80 deg.<ADC = 180-<BCD = 180–80 = 100 deg, so <ADB = 100/2 = 50 deg.

IABCD is a rhombus and ACB = 40 deg. What is the value of <ADB?Since <ACB = 40 deg, <BCD = 2*<ACB = 80 deg.<ADC = 180-<BCD = 180–80 = 100 deg, so <ADB = 100/2 = 50 deg.Another approach: Let AC and BD intersect at O.

IABCD is a rhombus and ACB = 40 deg. What is the value of <ADB?Since <ACB = 40 deg, <BCD = 2*<ACB = 80 deg.<ADC = 180-<BCD = 180–80 = 100 deg, so <ADB = 100/2 = 50 deg.Another approach: Let AC and BD intersect at O.There are 4 right angled triangles: In triangle OBC, <OCB = 40 deg, so <CBO = 90–40 = 50 deg which is the same as <ADB.

Similar questions