Physics, asked by amisuman, 6 hours ago

Help please.. for the below question related to vectors

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Answered by tben47175

0

|A|=1

also ,The magnitude of given vector is also given by,

|A|= $\sqrt{4 + {x}^{2} + 9 }$

1 = 16 + x²

x² + 15 = 0

x = $\sqrt{ 15}$

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