Math, asked by tusharram2002, 11 months ago

help please help help help please help help help help please​

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Answered by sanika04kapre
1

Answer:

sin theta + cos theta = √ 2 cos theta

sin (90- theta) = cos theta

sin theta = cos (√2-1)

sin / cos =√2-1

tan theta= √2-1

cot theta = 1/√2-1

= after rationalising

= √ 2+1

Answered by Anonymous
2

Answer:

 \sin( \infty )  +  \cos( \infty )  =  \sqrt{2}  \cos( \infty )  \\  \sin( \infty )  =  \cos( \infty ) ( \sqrt{2}  - 1) \\  \frac{ \sin( \infty ) }{ \cos( \infty ) }  =  \sqrt{2}  - 1 \\  \tan( \infty )  =  \sqrt{2}  - 1

 \cot( \infty )  =  \frac{1}{ \sqrt{2} - 1 }  \\  \cot( \infty )  =  \frac{1}{ \sqrt{2} - 1 }  \times  \frac{ \sqrt{2}  + 1}{ \sqrt{2}  + 1}  \\  \cot( \infty ) =  \sqrt{2}  + 1

Hope it helps you friend. ✌

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