Question

help please i am in quick hurry tommorow is my test​

Answer 1

Question:-

Rahul travels 2 km towards east then turns and travels 3 km towards north and then again travels 2 km towards east. It tooks him overall 45 min to do so. Find his:

(i) Speed

(ii) Velocity

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Given:-

• Distance towards east = 2 km

• Distance towards North = 3 km

• Distance again towards east = 2 km

• Time take to travel = 45 min

To Find:-

• His Speed

• His Velocity

Formulas Used:-

• ${\boxed{\bf{Speed=\dfrac{Distance}{Time}}}}$

• ${\boxed{\bf{Velocity=\dfrac{Displacement}{Time}}}}$

Solution:-

Firstly,

Time Taken = 45 min = 45/60 hrs = 3/4 hrs

So,

(i)

$\sf:\implies\:Speed=\dfrac{Distance}{Time}$

$\sf:\implies\:Speed=\dfrac{2+3+2}{\dfrac{3}{4}}$

$\sf:\implies\:Speed=\dfrac{7\times4}{3}$

$\sf:\implies\:Speed=\dfrac{28}{3}$

$\sf:\implies\:Speed=9.\overline{33}kmh^{-1}$

Hence, His Speed is 28/3 km/h or 9.33 km/h.

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(ii)

Displacement = $\sqrt{2^2+1.5^2}+\sqrt{2^2+1.5^2}$ km

Displacement = $\sqrt{6.25}+\sqrt{6.25}$ km

Displacement = $2.5 + 2.5$ km

Displacement = $5$ km

$\sf :\implies\:Velocity=\dfrac{Displacement}{Time}$

$\sf :\implies\:Velocity=\dfrac{5}{\dfrac{3}{4}}$

$\sf :\implies\:Velocity=\dfrac{5\times4}{3}$

$\sf :\implies\:Velocity=6.66kmh^{-1}$

Hence, His Velocity is 20/3 km/h or 6.66 km/h.

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Answer 2

✧══════•❁❀❁•══════✧$\huge\color{purple}\boxed{\colorbox{black}{❥αɳรωεɾ:-}}$

Given:-

Distance towards east = 2 km

Distance towards North = 3 km

Distance again towards east = 2 km

Time take to travel = 45 min

To Find:-

His Speed

His Velocity

Formulas Used:-

${\boxed{\bf{Speed=\dfrac{Distance}{Time}}}}$

${\boxed{\bf{Velocity=\dfrac{Displacement}{Time}}}}$

Solution:-

Firstly,

Time Taken = 45 min = 45/60 hrs = 3/4 hrs

So,

(i)

$\sf:\implies\:Speed=\dfrac{Distance}{Time}$

$\sf:\implies\:Speed=\dfrac{2+3+2}{\dfrac{3}{4}}$

$\sf:\implies\:Speed=\dfrac{7\times4}{3}$

$\sf:\implies\:Speed=\dfrac{28}{3}$

$\sf:\implies\:Speed=9.\overline{33}kmh^{-1}$

Hence, His Speed is 28/3 km/h or 9.33 km/h.

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(ii)

Displacement = $\sqrt{2^2+1.5^2}+\sqrt{2^2+1.5^2}$ km

Displacement = $\sqrt{6.25}+\sqrt{6.25}$ km

Displacement = $2.5 + 2.5$ km

Displacement = $5$ km

$\sf :\implies\:Velocity=\dfrac{Displacement}{Time}$

$\sf :\implies\:Velocity=\dfrac{5}{\dfrac{3}{4}}$

$\sf :\implies\:Velocity=\dfrac{5\times4}{3}$

$\sf :\implies\:Velocity=6.66kmh^{-1}$

Hence, His Velocity is 20/3 km/h or 6.66 km/h.

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