help please I will mark brainlist
Answers
Answer:
1-(i) 2⁷
(ii) 7³
2- 2⁴=16 and 11²=121
3- 3² is greater
4- 40
5-(i) 3⁴ and (i) 10³
6-19683
7- 4*10⁵
10-(i) 1*1*1=1 and (i) 1+1+1=3
Step-by-step explanation:
sorry for rest answers..!!!
Answer:
1. 2⁷
7³
2. 16
121
3. 3² > 2³
4. 40
5. 3⁴
10³
6. (-3)⁹
7. 4 × 10⁵
4.3209 × 10³
8. 12³ or (3³ × 4³)
32a⁵
9. 30721
900315
10. 1
3
Step-by-step explanation:
1.
i) 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2 = 2⁷
ii) 343 = 7 × 7 × 7 = 7³
2. 2⁴ = 2 × 2 × 2 × 2 = 16
11² = 11 × 11 = 121
3. 3² = 3 × 3 = 9 and 2³ = 2 × 2 × 2 = 8
so, 3² > 2³
4. (-5) × (-2)³ = ((-5) × (-2)) × ((-2) × (-2)) = 10 × 4 = 40
(Note: You dont have to group it always we can group it to make the problem easier)
5. i) 3 × 3 × 3 × 3 = 3⁴
ii) 10 × 10 × 10 = 10³
6. We know that (a^m) × a^n = a^(m + n)
so, (-3)⁴ × (-3)⁵ = (-3)⁹
(-3)⁹ = (-19683)
7.
i) 400000 = 4 × 10⁵ (Here the easy way to find is just that add the number of zeros)
ii) 4320.9 = 4.3209 × 10³ (Shift the decimal places after the first digit)
8.
i) (3 × 4)³ = 12³ or (3³ × 4³)
ii) (2a)⁵ = 2⁵ × a⁵ = 32a⁵
9.
i) 3 × 10⁴ = 30000
7 × 10² = 700
2 × 10¹ = 20
10⁰ = 1
Adding we get = 30721
ii) 9 × 10⁵ = 900000
3 × 10² = 300
10¹ = 10
5 × 10⁰ = 5 × 1 = 5
Adding we get = 900315
10.
i) 3⁰ × 7⁰ × 2⁰ = 1 × 1 × 1 = 1
ii) 5⁰ + 3⁰ + 1⁰ = 1 + 1 + 1 = 3
Hope you understood it........All the best