Question

HELP PLEASE
If a:b = 5:8 and b:c = 24:19, find a:b:c

Answer 1

Step-by-step explanation:

$\frac{a}{b} = \frac{5}{8}$

Let x be the common multiple of 5 and 8.

So, a = 5x and b = 8x

Similarly, let y be the common multiple of 24 and 19.

So, b = 24y and c = 19y

Here, b = 8x = 24y

⇒ x = 3y

Now, a:b:c = 5x : 24y : 19y

= 5(3y) : 24y : 19y ( since x = 3y)

= 15y : 24y : 19y

Therefore the answer is 15:24:19.

Answer 2

Answer:

This Is Just an Example of the same

Given that a:b=5:9 and b:c=4:7.

Here the common term is b which is found in both the ratios.

Ok now let’s look at the value of b in 1st ratio. It is 9. And 4 in the second.

Now we have to take the LCM of these two values so that we are changing the value of b into the LCM value in both the ratios. The LCM is 36.

So we change the value of b into 36 in the 1st and 2nd ratio. 9*4=36. So multiply the whole 1st ratio by 4 making a:b=20:36

Similarly change the value of b as 36 in the second ratio. 4*9=36. Hence multiply the entire second ratio by 9 making b:c=36:63.

Now that the value of b in both the ratio being same we can concatenate them. Hence a:b:c=20:36:63.

Hope you understand the logic!