Question

Help please in this question







​

Answer 1

Step-by-step explanation:

I think angle DAE is 60°

hope it will help you

Answer 2

Answer:

22.5 deg

Step-by-step explanation:

given: ABCD is a square with BD as its diagonal

: AD = ED

Since ABCD is a parallelogram, The diagonal BD bisects the angle D.

= <ADB = <ADC/2 = 90/2 = 45 *

since the line BD is extended, and BDE is a line segment, we can say that <ADE and <ADB is a linear pair.

So, 180 - <ADB = <ADE

= 180 - 45 = 135 - (1)

Now, we know that AD=DE and ADE is a triangle.

So, <DAE = <DEA - (2)

and <DAE + <DEA = 45 (exterior angle-sum property)

= 2(<DAE) = 45

= <DAE = 45/2 = 22.5

OR!

<DAE + <DEA + <ADE = 180 (angle-sum property of a triangle)

= 2(<DAE) + <ADE = 180

= 2(<DAE) + 135 = 180

= 2(<DAE) = 180 - 135 = 45

= <DAE = 45/2 = 22.5

Therefore, <DAE = 22.5

Hope this explanation was what you were looking for :)