Question

help please please please please​

Answer 1

$</p><p><font color="purple"></p><p></p><p>AP = AS, </p><p>BP= BQ, </p><p>CR= CQ and </p><p>DR= DS </p><p>⇒AP + BP + CR + DR = AS + BQ + CQ + DS </p><p></p><p>⇒ AB + CD = AD + CB </p><p>But AB = CD and AD = CB</p><p></p><p> ∴ AB = AD Hence, ABCD is a square.</p><p></p><p></font></p><p></p><p>$

Answer 2

Solution :

Given :

• ABCD is rectangle circumscribed in a circle.

To prove :

• ABCD is square

Proof :

We know that tangents from an external point are equal,

=> AP = AS........(1)

=> BP = BQ........(2)

=> CR = CQ........(3)

=> DR = DS.........(4)

Adding (1), (2), (3) and (4)

=> AP + BP + CR + DR = AS + BQ + CQ + DS

=> AB + DC = AD + BC

Also, AB = CD and AD = BC as ABCD is a rectangle.

=> AB + AB = AD + AD

=> 2AB = 2AD

=> AB = AD

•°• ABCD is a square with all equal sides.

Hence proved!