Question

Help Please.Poor in Maths.Please write in paper no text.No Spamming please​

Answer 1

Answer:

$(\frac{9x}{6}+\frac{y}{5})(\frac{9x}{6}-\frac{y}{5})$

Step-by-step explanation:

$=\frac{81{x}^2}{36}-\frac{{y}^2}{25}$

$={(\frac{9x}{6})}^2-{(\frac{y}{5})}^2$

${a}^2-{b}^2=(a+b)(a-b)$

$=(\frac{9x}{6}+\frac{y}{5})(\frac{9x}{6}-\frac{y}{5})$

Answer 2

Your Answer:

$\tt \frac{81}{36} {x}^{2} - \frac{ {y}^{2} }{25} \\\\ \tt = { (\frac{9}{6}x )}^{2} - {( \frac{y}{5}) }^{2} \\\\ \tt Using \: identities \: a^{2}-b^{2}=(a-b)(a+b)\\\\ \tt = ( \frac{9}{6} x - \frac{y}{5} )( \frac{9}{6} x + \frac{y}{5} ) \\\\ \tt = ( \frac{3}{2} x - \frac{y}{5} ) ( \frac{3}{2} x + \frac{y}{5} )$

Concepts Used:

• Algebraic Identities - a²-b²=(a-b) (a+b)
• Mathematical Solvings
• Square and Square Roots