Question

help please! question is in picture

Answer 1

Question:

$\sqrt{ \frac{a - 3x}{2x + b} } = \frac{1}{3}$

Solution:

$\sqrt{ \frac{a - 3x}{2x + b} } = \frac{1}{3}$

by squaring both side we get,

$\frac{a - 3x}{2x + b} = \frac{1}{9} \\ \\9( a - 3x )= 1(2x + b) \\ \\ 9a - 27x = 2x + b \\ \\ - 27x - 2x = b - 9a \\ \\ - 29x = b - 9a \\ \\ x = - \frac{b - 9a}{29}$