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Answer 1

Answer:

Since, total cards = 15

(i)  total odd no.'s from 1 to 15 = 8

    ∴ favorable outcomes= 8

   ∴ probability = 158

(ii) Total Multiples of 4 from 1 to 15 = 3

     ∴ favorable outcomes= 3

     ∴ probability = 153=51

(iii) Total no's divisible by 5 from 1 to 15 = 3

     ∴ favorable outcomes= 3

    ∴ probability = 153=51

(iv) Total no's divisible by 2 and 3 from 1 to 15 are:

       6,12

       ∴ favorable outcomes= 2

    ∴ probability = 152

(v) Total no's less than or equal to 10 from 1 to 15 = 10

     ∴ favorable outcomes= 10

    ∴ probability = 1510=32

Answer 2

Answer:

$(i) \frac{1}{3}$

$(ii) \frac{11}{21}$

$(iii) \frac{3}{7}$

Step-by-step explanation:

Given,

Total no. of outcomes = 21

Solution:

(i) Numbers that are divisible by 3 within 1 to 21

= 3, 6, 9, 12, 15, 18 and 21 = 7 numbers

Therfore, probability of getting a card divisible by 3 is

$= \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

$= \frac{7}{21}$

$= \frac{1}{3} (ans)$

(ii) No. of odd cards within 1 to 21 are

= 1, 3, 5, 7, 9, 11, 13, 15, 17, 19 and 21

= 11 numbers

Therefore, Probability of getting odd numbered cards is

$= \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

$= \frac{11}{21} (ans)$

(iii) No. of cards divisible by both 3 and 7 within 1 to 21 are

= 3, 6, 7, 9, 12, 14, 15, 18 and 21

= 9 numbers

Therefore, Probability of getting cards divisible by both 3 & 7 is

$= \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

$= \frac{9}{21}$

$= \frac{3}{7} (ans)$

Result:

(i) 1/3

(ii) 11/21

(iii) 3/7