Help please :)
The sum of the digits of a two digit number is 8 and the diffrence between the number and that formed by reversing its digits is 18.Find the number.
Class 10 CBSE
Pair of linear equations in two variables.
- Cahira :)
Answers
Answered by
2
Any two digit number can be written in the form = 10x+y
In this particular case, you have your
x+y=8−−−(1)
After reversing, our number becomes =10y+x
(10x+y)−(10y+x)=18
=>10x+y−10y−x=18
=> 9x−9y=18
=> x−y=2−−−−(2)
Add equation 1 and 2.
x−y=2
x+y=8
=>2x=10
=>x=5
Putting the value of x as 5, we get y as,
=x+y=8
=> 5+y=8
=> y=3
So the number is :
(10∗5)+3=53
Hope this makes ur day better!!
Answered by
0
Answer:
GIVEN. THAT
x+y= 8 ( sum of digits of two digit no.)
and - (I)
10x + y - (10y+x) = 18 (difference as per the question)
9x - 9y = 18
x-y = 2 -(II)
now add I AND II
2x = 10
x = 5
and y = 3
no.is 53
Similar questions