Math, asked by nikhil4946, 9 months ago

HELP PLEASE VERY URGENTTTT​

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Answered by Anonymous
1

Answer

- 18abc

solutions

given

a - 2b + 3c = 0 ---(1

Now

(a^3 - (2b)^3 +(3c)^3 = - 3(a)(2b)(3c) + (a - 2b +3c)( a^2 + 4b^2 + 9c^2 + 2ab +6bc - 3ca)

a^3 - 8b^3 + 27c^3 = - 18abc + 0

from given --(1 ) anything multiple of 0 is 0

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