Question

help pls math question std 9​

Answer 1

Answer:

ANGLE ADB = 95°

AND

ANGLE ADC=85°

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Answer 2

Answer:

Given

Angle B= 70°

Angle C= 80°

By angle sum property of a triangle

Angle A+ Angle B+ Angle C= 180°

Angle A+ 70°+80°= 180°

Angle A+150°= 180°

Angle A= 180°-150°=30°

Since, AD is bisector of Angle A

Therefore, Angle BAD= Angle CAD= 30°/2= 15°

In ∆ADB,

Angle B+ Angle ADB+ Angle BAD= 180°

70°+Angle ADB+ 15°= 180°

Angle ADB+ 85°= 180°

Angle ADB= 180°-85°= 95°

In ∆ADC,

Angle C+ Angle ADC+ Angle CAD= 180°

80°+Angle ADC+ 15°= 180°

Angle ADC+ 95°= 180°

Angle ADC= 180°-95°=85°