Question

help pls.plss.plsss.i am confused ​

Answer 1

Ah mate u r confused in this wait I will tell u ⤵

RULE ⤵

IN ANY RIGHT ANGLED TRIANGLE THE LENGTH OF HYPOTENUSE ( SIDE OPPOSITE TO 90°) = WHOLE ROOT OF LEG 1^2 + LEG 2^2 OR THE SQUARE OF HYPOTENUSE IS EQUAL TO SQUARE OF LEG 1 & LEG 2 .

EXAMPLE ⤵

CONSIDER A RIGHT ANGLED TRIANGLE AOB WHERE ANGLE 0 = 90° AND SIDE AB IS OPPOSITE TO ANGLE O SO

${(ab)}^{2} = {(oa)}^{2} + {(ob)}^{2}$

So according to question ⤵

Hypotenuse = 5cm

LEG 1 = 4cm

LEG 2 = ???? so

$= = > {5}^{2} = {4}^{2} + {x}^{2} \\ = = > 25 = 16 + {x}^{2} \\ = = > 25 - 16 = {x}^{2} \\ = = > 9 = {x}^{2} \\ = = > 3 = x$

SO LEG 2 = 3cm

HOPE IT HELPS ☺♥️

TRY NOT TO MARK ME BRAINLIEST

PHYSICS, CSK, DHONI LOVER ♥️