Math, asked by aWitSu, 2 months ago

HELP PLSS
ASAP
Mrs. Agbuya invested Php10,000 more than her husband did. If they both
invested the money at 5% per year and their combined income from the
investments was Php4,000.00, how much did each invest

Answers

Answered by pulakmath007
5

SOLUTION

GIVEN

Mrs. Agbuya invested Php 10,000 more than her husband did.

They both invested the money at 5% per year

Their combined income from the investments was Php 4,000.00,

TO DETERMINE

The investment of each

EVALUATION

Here it is given that Mrs. Agbuya invested Php 10,000 more than her husband did.

Let Mr. Agbuya invested Php x

So Mrs. Agbuya invested Php ( x + 10,000 )

Now total investment

= Php ( x + x + 10,000 )

= Php ( 2x + 10,000 )

It is also given that they both invested the money at 5% per year

So total combined income from the investments

 \displaystyle \sf{ = Php \:  \: \frac{(2x + 10000) \times 5 \times 1}{100}  }

 \displaystyle \sf{ = Php \:  \: \frac{(2x + 10000) }{20}  }

So by the given condition

 \displaystyle \sf{  \frac{(2x + 10000) }{20}  = 4000 }

 \displaystyle \sf{ \implies \:  (2x + 10000) = 4000  \times 20}

 \displaystyle \sf{ \implies \:  (2x + 10000) = 80000}

 \displaystyle \sf{ \implies \:  2x = 80000 - 10000}

 \displaystyle \sf{ \implies \:  2x = 70000}

 \displaystyle \sf{ \implies \:  x = 35000}

Hence

Mr. Agbuya invested Php 35000

Mrs. Agbuya invested Php 45000

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