Question

help plss (wrong answer will be reported)​

Answer 1

Answer:

Q1)Hence, the 10th term of A.P is 33

Q2)2(d−c)

Q3)0(solution in photo)

Q4)2b=a+c

Q5)n(n+1)/root 2

Q6)35

Q7)17

Q8)The given terms are 2k + 1, 3k + 3 and 5k − 1. Hence, the value of k for which the given terms are in an AP is 6.

Q9)incomplete

Step-by-step explanation:

Q2)Let x be the common difference of the A.P. a,b,c,d,e,f.

As e is the 5th term

∴e=a+(5−1)x(∵a  

n

​

=a+(n−1)d), where a_n is the nth term

⇒e=a+4x    ...(1)

and c=a+2x     ...(2)

∴ Using equation (1) and (2), we get

e−c=a+4x−a−2x

⇒e−c=2x=2(d−c)

​Q6)P=3+5+7+...(n terms)

a=3

d=5-3=2

∴P=  

2

n

​

[2.3+(n−1)2]=n  

2

+2n