Math, asked by XxKunjanxX, 1 month ago

help plz..

No spam..

really want ur help..​

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Answers

Answered by rahulgowdaharish08
7

Step-by-step explanation:

if we simplify√p2q2

so the answer is

-1

Attachments:
Answered by Aryan0123
22

Solution:

First consider the term inside the square root and simplify it as much as possible.

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In this question,

p²q² can also be written as (pq)²

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Now we know that this number is in square root.

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  \sf{\sqrt{ {p}^{2}  {q}^{2} } } \\  \\

 =   \sf{\sqrt{(pq)^{2} } } \\  \\

Now, here we use a property.

 \bf{A \: number \: in \: square \: root = x ^ { \frac{1}{2} } }

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So, the expression becomes:

 \hookrightarrow \:  \sf{pq^{2 \times  \frac{1}{2} } } \\  \\

 \implies \sf{pq^{ \cancel{2} \times  \frac{1}{ \cancel{2}} } } \\  \\

\implies \: \sf{pq^{1} } \\  \\

 \therefore \boxed{ \bf{ \sqrt{p^{2}q ^{2} } = pq }} \\  \\

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