Question

Help plz plz!!!!!!!!

Answer 1

Let a = 9; b = 12; c = 5; and d = 8.
Using Brahmagupthas formula, area of cyclic quadrilateral is
$\sqrt{(s - a)(s - b)(s - c)(s - d)} \\ s = \frac{a + b + c + d}{2} \\ here \: \: s = \frac{9 + 12 + 5 + 8}{2} = 17 \\ area = \\ \sqrt{(17 - 9)(17 - 12)(17 - 5)(17 - 8)} \\ = \sqrt{8 \times 5 \times 12 \times 9} = 12 \sqrt{30}$