help plz solve this question
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Hey Mate
your answer is ---
Given, sides of a triangle are m^2-n^2 and 2mn
so, by Pythagoras theorem
hypotenuse = (m^2-n^2)^2 + (2mn)^2
= m^4+n^2-2m^2n^2 +4m^2n^2
= m^4+n^4 +2m^2n^2
so, hypotenuse = (m^2+n^2)^2
hope it helps you
your answer is ---
Given, sides of a triangle are m^2-n^2 and 2mn
so, by Pythagoras theorem
hypotenuse = (m^2-n^2)^2 + (2mn)^2
= m^4+n^2-2m^2n^2 +4m^2n^2
= m^4+n^4 +2m^2n^2
so, hypotenuse = (m^2+n^2)^2
hope it helps you
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