Question

help plz very urgent quick
plz don't spam​

Answer 1

Answer:

This I one way to find the angles

Answer 2

Answer:

In triangle ∆ABD

angle D = 45°

Angle B=25°

Angle A=a°

45°+25°+a=180°

70°+a=180°

a=180°-70°

a=110°

In triangle ∆BCD

Angle A=Angle B=110° ( opposite angles equal)

Angle C=25°(A.I.A)

25°+110°+d°=180°

135°+d=180°

d=180°-135°

d=35°

This is the answer