Question

help........................ Question 5

Answer 1

hey dear,

here is your answer.......

let the base of triangle=x cm

so acc to quest.

perpendicular={x-7} cm

hypotenuse=13cm

acc to pythagoras theorem

[hypotenuse^2]=[perpendicular^2]+[base^2]

(13)^2=(x-7)^2 +x^2

169=(x^2)-14x+49+(x^2)

(2{x^2})-14x-120=0

(x^2)-7x-60=0

after solving x=13.1cm and perpendicular=6.1cm

hope it helps you

thanks for giving me this opportunity to help you

:) :) :) :)

Answer 2

Okay mate let's check your answer
The figure is a Right Angled Triangle , hence altitude is equal to the side adjacent to the Hypotenuse

Let's take the base of the Triangle as x cm
So the altitude will be x - 7 cm

So According to Pythagoras Theorem
Hypotenuse (sq) = base (sq) + altitude (sq)
13 (sq) = x(sq) + x - 7(sq)
169 = x(sq) + x(sq) + 49 - 14x
2x(sq) - 14x - 120 = 0
Now it's a Quadratic Equation, lets factorise it

x(sq) - 7x - 60 = 0
x(sq) - 12x + 5x - 60 =0
x(x - 12) + 5(x - 12) = 0
(x +5) ( x - 12) = 0
x +5 = 0 or x - 12 = 0
x = -5 or x = 12

Now the length of a side cannot be negative so the answer is 12cm
Base 12 cm
And altitude x - 7 = 12 - 7 = 5 cm
Hence Base = 12cm
Altitude= 5cm

Hope it helps