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Question 9
In the given figure O is centre of circle and ab BC CD and AD are tangents the circle if angle BOC 89 degree then angle a body is equal to

Answer 1

Answer:

1.89. (opposite angle property)

Answer 2

$\angle AOD=91^{\circ}$

Step-by-step explanation:

O is the center of circle.

Angle BOC=89 degrees

AB, BC,CD and AD are tangent of the circle

We know that

When a quadrilateral circumscribing a circle then, opposite side  of  quadrilateral subtended supplementary angles at the center of inscribed circle.

Therefore, by using this property

$\angle AOD+\angle BOC=180^{\circ}$

Substitute the values then we get

$\angle AOD+89=180$

$\angle AOD=180-89=91^{\circ}$

$\angle AOD=91^{\circ}$

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