Question

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Answer 1

Answer:in triangle ABC and ADE:-

Angle a is common

AD/AB=AE/AC (as AD/AB=AE/EC so after the reciprocal if we subtract 1 we would get AD/AB=AE/AC)

hence triangle ADE is similar to triangle ABC and as

angle ADE =angle AED

So angle ABC=angle ACB

Hence equal angle have equal opposite sides so AB=AC and ABC is isosceles triangle

Hope it helps u.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given,

AD/DB = AE/EC

Therefore, DE ∥ BC (Converse of Basic Proportionality Theorem)

So, ∠D = ∠B and ∠E = ∠C

But ∠D = ∠E (Given)

Therefore, ∠B = ∠C

So, AB = AC (Sides opposite to equal angles)

BAC is an isosceles triangle.

Hope it helps