Question

help..(step by step explanation)
A ball is released from the top of a tower of height h meters. It takes T seconds to reach the ground. What is the position of the ball in T/3 seconds?

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Answer 1

Answer:

Explanation:

the acceleration of the ball will be g. Initial velocity will be 0.  

in T sec. body travels h mts.  

s = ut+1/2gtsquare if we apply ]

h=(1/2)gT  square ----1

in T/3 sec

h1 =1/2gtsquare

=1/2Xg(Tsquare/9) ---2

 so from 1 and 2

h1 = h/9

h-h/9 = 8h/9

P L S M A R K M E A S B R A I N L I L E S T..