HELP (step by step explanation pls)
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Step-by-step explanation:
In ∆ABC O is a midpoint of BC , AOB = 90 ° OA = 12cm and OC = 6.5 cm
Since mid-point of the hypotenuse of a right triangle is equidistant from the vertices.
∴CA=CB=OC⇒CA=CB=6.5 cm⇒AB=13 cm
In right triangle OAB, we have
AB
2
=OB
2
+OA
2
⇒13
2
=OB
2
+12
2
⇒OB=5
∴ar(△AOB)=
2
1
(OA×OB)=
2
1
(12×15)=30 cm
2
Answered by
3
Answer:
Since mid-point of the hypotenuse of a right triangle is equidistant from the vertices.
∴CA=CB=OC⇒CA=CB=6.5 cm⇒AB=13 cm
In right triangle OAB, we have
AB
2
=OB
2
+OA
2
⇒13
2
=OB
2
+12
2
⇒OB=5
∴ar(△AOB)=
2
1
(OA×OB)=
2
1
(12×15)=30 cm
2
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