Question

help to complete the sum ​

Answer 1

Let =12(E01)

=3(E02)

Given: 2−13=4⟹1−1=4⟹−=4

⟹−=4(E03)

From (E01) and (E02) :

=12⋅3=32(E04)

273−183=(3)3−(12)3

⟹3−3=(−)3+3(−)(E05)

From (E03), (E04) and (E05) :

273−183=(4)3+3(4)

⟹273−183=64()3+12()2(E06)

From (E04) and (E06) :

273−183=[64⋅(32)3]+[12⋅(32)2]

=(8×27)+(3×9)=216+27=243

Ans: 243 Answer:

Answer 2

Answer:

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