Math, asked by chiraggarg1708, 1 year ago

Help to solve it please

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Answered by Anonymous
0

Answer:

Step-by-step explanation:

LHS

Sina-cosa+1/sina+cosa-1

Divide numerator and denominator by cosa

Tana-1+seca/tana+1-seca

Tana-1+seca/tana-seca+sec^2a - tan^2 a

(By identity)

Tana-1+seca/(seca-tana)(tana-1+seca)

(Taking common out)

Numerator and denominator gets cancelled leaving 1/seca-tana

=RHS

Therefore, LHS = RHS

#MarkAsBrainliest

Answered by SwaggerGabru
0

Answer:

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved

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