Question

help to solve it with their method..

Answer 1

here is ur answer dear...........
there is a property that,
{x^n-a^n}/{x-a}=na^{n-1}
so divide and multiply this expression with (x-3)
limit                  ( x^5-3^5)/x^3-3^3 *x-3/x-3
(x tends to 3)
so this above expressed identity applies to it
and it will be....
5*3^4/3*3^2
5*3
15
 
thanks........
hope it helps uh
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