Math, asked by studentrishav2007, 18 days ago

help to solve pleas​

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Answers

Answered by predyyyt
1

Step-by-step explanation:

How to solve your problem

(

2

+

3

)

2

4

2

(2a+3b)^{2}-4c^{2}

(2a+3b)2−4c2

Simplify

1

Expand the square

(

2

+

3

)

2

4

2

\left(2a+3b\right)^{2}-4c^{2}

(2a+3b)2−4c2

(

2

+

3

)

(

2

+

3

)

4

2

(2a+3b)(2a+3b)-4c^{2}

(2a+3b)(2a+3b)−4c2

2

Distribute

(

2

+

3

)

(

2

+

3

)

4

2

{\color{#c92786}{(2a+3b)(2a+3b)}}-4c^{2}

(2a+3b)(2a+3b)−4c2

2

(

2

+

3

)

+

3

(

2

+

3

)

4

2

{\color{#c92786}{2a(2a+3b)+3b(2a+3b)}}-4c^{2}

2a(2a+3b)+3b(2a+3b)−4c2

3

Distribute

2

(

2

+

3

)

+

3

(

2

+

3

)

4

2

{\color{#c92786}{2a(2a+3b)}}+3b(2a+3b)-4c^{2}

2a(2a+3b)+3b(2a+3b)−4c2

4

2

+

6

+

3

(

2

+

3

)

4

2

{\color{#c92786}{4a^{2}+6ab}}+3b(2a+3b)-4c^{2}

4a2+6ab+3b(2a+3b)−4c2

4

Distribute

4

2

+

6

+

3

(

2

+

3

)

4

2

4a^{2}+6ab+{\color{#c92786}{3b(2a+3b)}}-4c^{2}

4a2+6ab+3b(2a+3b)−4c2

4

2

+

6

+

6

+

9

2

4

2

4a^{2}+6ab+{\color{#c92786}{6ab+9b^{2}}}-4c^{2}

4a2+6ab+6ab+9b2−4c2

5

Combine like terms

4

2

+

6

+

6

+

9

2

4

2

4a^{2}+{\color{#c92786}{6ab}}+{\color{#c92786}{6ab}}+9b^{2}-4c^{2}

4a2+6ab+6ab+9b2−4c2

4

2

+

1

2

+

9

2

4

2

4a^{2}+{\color{#c92786}{12ab}}+9b^{2}-4c^{2}

4a2+12ab+9b2−4c2

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Solution

4

2

+

1

2

+

9

2

4

2

Answered by shreekantbprail
25

Answer:

hope this is helpful to you

answer

thanks

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