help to solve the 6 the question please
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Answered by
3
Heya friend here's your answer.
We know that,
Sin theta = cos(90-theta)
Therefore,
cos(90-theta) = cos(3theta - 30)
⏩90-theta = 3theta - 30
⏩theta = 30
Therefore,
tan theta = 1/root 3...
Hope this helps you...
rohitkumargupta:
option is showing for cut
agh sorry about the spaces
I did it in the website and didn't use tags
its ok
ok
now it's correct
tabhi
se dekh hin rhi thi
haan
ohk
Answered by
7
HELLO DEAR,
let theta=A
A and (3A-90). are acute angle
such that
sinA=cos(3A-30) [sin(90-A)=cosA]
sinA=sin90-{3A-30}
A=90-3A+30
A+3A=120
4A=120
A=120/4
A=30°
tan A= tan30° =1/√3
I HOPE ITS HELP YOU DEAR,
THANKS
let theta=A
A and (3A-90). are acute angle
such that
sinA=cos(3A-30) [sin(90-A)=cosA]
sinA=sin90-{3A-30}
A=90-3A+30
A+3A=120
4A=120
A=120/4
A=30°
tan A= tan30° =1/√3
I HOPE ITS HELP YOU DEAR,
THANKS
tq
welcome
good :)
thanks dear
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