Question

help to solve the 6 the question please

Answer 1

Heya friend here's your answer. We know that, Sin theta = cos(90-theta) Therefore, cos(90-theta) = cos(3theta - 30) ⏩90-theta = 3theta - 30 ⏩theta = 30 Therefore, tan theta = 1/root 3... Hope this helps you...

Answer 2

HELLO DEAR,
let theta=A

A and (3A-90). are acute angle

such that

sinA=cos(3A-30) [sin(90-A)=cosA]

sinA=sin90-{3A-30}

A=90-3A+30

A+3A=120

4A=120

A=120/4

A=30°

tan A= tan30° =1/√3

I HOPE ITS HELP YOU DEAR,
THANKS