Question

Help to solve this out from the ch Playing With Numbers.​

Answer 1

Answer:

Let the numbers be x and y

the number at ones place is y

and number on tens place is 10x

so the digit will be 10x+y

The interchange of digit is =10y+x

It is given the difference between the digit and interchange is 63 so

10x+y−(10y+x)=63

9x−9y=63

x−y=7

Step-by-step explanation:

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Answer 2

Answer:

if the Number obtained after interchanging is 63 , original number should have been 36. So the difference is 3.

only problem: sum of the digits is Not 15. so the Question has typo error. 63 should be 69.