Question

help to solve this question​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{solution}}$

${x}^{2} - 6x + 5 \\ \\ on \: comparing \: {x}^{2} - 6x + 5 \: with \: a {x}^{2} + bx + c \\ \\ a = 1 \: \: \: b = - 6 \: \: c = 5 \\ \\ sum \: of \: zeroes \: = \frac{ - b}{a} \\ \\ = \frac{ - ( - 6)}{1} \\ \\ = 6 \\ \\ product \: of \: zeroes \: = \frac{c}{a} \\ \\ = \frac{5}{1} \\ \\ = 5$