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A.P. = ✓a, 3✓a, 5✓a
d = 3✓a - ✓a = 5✓a - 3✓a
d = 2✓a = 2✓a
d=2✓a
As the common difference is same so these terms are in A.P.
hope this helps you....:)
d = 3✓a - ✓a = 5✓a - 3✓a
d = 2✓a = 2✓a
d=2✓a
As the common difference is same so these terms are in A.P.
hope this helps you....:)
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