help us guys please
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Given that :
∠GED = 135°
To find :
∠AGE , ∠GEF, ∠FGE
Solution:
∠GED = ∠GEF + ∠FED
135° = ∠GED + 90°
∠GED = 45°
AB || CD & FE is the transversal
so, ∠FED = ∠EFB = 90°
∠EFB = ∠EFG = 90° ( perpendicular)
In ΔEFG
∠EFG + ∠GEF +∠ FGE = 180°
So , ∠FGE = 45°
∠FGE + ∠AGE = 180°
∠AGE = 135°
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