Question

help with image please​​

Answer 1

We know that :-

➝ Area of rhombus = 1/2 × (product of length of diagonals of rhombus )

➝Length of diagonal (1) = 7.5 cm

➝Length of diagonal (2) = 12 cm

➝ Area of given rhombus = ( 1/2 )× 7.5 × 12

➝ (1/2) × (75/10) × 12

➝ (75/10) × 6

➝ (75×6) / 10

➝ 450 / 10 = 45 cm²

Area of rhombus = 45 cm²

Additional Information :

Area of circle = π r²

Area of square = (side)²

Area of rectangle = length × breath

Circumference of circle = 2πr

Perimeter of square = 4 × side

Perimeter of rectangle = 2( length+breadth)

Perimeter of any figure = sum of all sides of that figure

Answer 2

$\bold{\underline{Given :-}}$

• 1st diagonal = 7.5 cm
• 2nd diagonal = 12 cm

$\bf \underline {To \: Find :- }$

• It's area

$\bf \underline{Solution :-}$

We know that,

$\bigstar \bold \red{Area \: of \: Rhombus = ½ \: \times d_{1} \times d_{2} }$

$\therefore \bf{Area \: of \: the \: Rhombus = ½ \: \times 7.5 \times 12 } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 7.5 \times 6 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \: =45$

$\sf{Hence, it's \: area \: is \: 45 \: {cm}^{2} . }$