Question

HELP WITH THIS ASAP WRONG ANSWERS GET DELETED AND REPORTED

Answer 1

Answer:

4/9(x⁰y⁰)

Step-by-step explanation:

Given: $\tt{ (\dfrac{x^{2}y^{-1}}{6y^{2}})^{-2} \ . (\dfrac{x^{2}y^{-2}}{9y})^{2} }$

$\tt{ \implies (\dfrac{x^{2}}{6y^{2}.y})^{-2} \ . (\dfrac{x^{2}}{9y.y^{2}})^{2} }$

$\tt{ \implies (\dfrac{x^{2}}{6y^{3}})^{-2} \ . (\dfrac{x^{2}}{9y^{3}})^{2} }$

$\tt{ \implies (\dfrac{6y^{3}}{x^{2}})^{2} \ . (\dfrac{x^{2}}{9y^{3}})^{2} }$

$\tt{ \implies \dfrac{(6y^{3})^{2}}{(x^{2})^{2}} \times \dfrac{(x^{2})^{2}}{(9y^{3})^{2}} }$

$\tt{ \implies \dfrac{36y^{6}}{x^{4}} \times \dfrac{x^{4}}{81y^{6}} }$

⇒ 4/9

⇒ 4/9(x⁰y⁰)